6x^2-3x=90

Solution for 6x^2-3x=90 equation:

6x^2-3x=90

We move all terms to the left:

6x^2-3x-(90)=0

a = 6; b = -3; c = -90;
Δ = b2-4ac
Δ = -32-4·6·(-90)
Δ = 2169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2169}=\sqrt{9*241}=\sqrt{9}*\sqrt{241}=3\sqrt{241}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3\sqrt{241}}{2*6}=\frac{3-3\sqrt{241}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3\sqrt{241}}{2*6}=\frac{3+3\sqrt{241}}{12}
$